Question

if a 370 kg missile is flying at a speed of 220 m/s, then what is its kinetic energy?
a 8,954,000 j
b 81,400 j
c 220 j
d 370 j

Explanation:

Step1: Recall Kinetic Energy Formula

The formula for kinetic energy (KE) is $KE = \frac{1}{2}mv^2$, where $m$ is mass (in kg) and $v$ is velocity (in m/s).

Step2: Substitute Values

Given $m = 370\ \text{kg}$ and $v = 220\ \text{m/s}$. Substitute into the formula:
$KE=\frac{1}{2}\times370\times(220)^2$
First, calculate $(220)^2 = 48400$. Then, $\frac{1}{2}\times370 = 185$. Now multiply $185\times48400 = 8954000\ \text{J}$.

Answer:

a. 8,954,000 J