Question

32
think for revisw
consider the following code segment.
num1 = 6
num2 = 4
num3 = 10
if (num1 < num2)
num1 = num2
else
num1 = num2
if (num2 > num1)
num1 = num2 + num1
sum = num1 + num2 + num3
what is the value of sum after the code segment is executed?
a 12
b 14
c 16
d 18

Explanation:

Step1: Initial Values

num1 = 6, num2 = 4, num3 = 10

Step2: First IF Condition

Check if num1 < num2 (6 < 4? No). So ELSE block: num1 = num2 → num1 = 4

Step3: Second IF Condition

Check if num2 > num1 (4 > 4? No). So no change here. Wait, wait, wait—wait, after first ELSE, num1 is 4. Now check num2 > num1: 4 > 4? No. Wait, maybe I misread. Wait, original first IF: num1 < num2? 6 < 4? No, so ELSE: num1 = num2 (4). Then next IF: num2 > num1? 4 > 4? No. Wait, but then sum is num1 + num2 + num3. Wait, no, maybe I made a mistake. Wait, let's re-examine. Wait, first IF: num1 < num2? 6 < 4? No, so ELSE: num1 = num2 (4). Then the next IF: num2 > num1? 4 > 4? No, so no change. Then sum = 4 + 4 + 10 = 18? Wait, no, the options have 18 as D? Wait, but let's check again. Wait, maybe the first IF is num1 < num3? Wait, the image is a bit unclear, but assuming the first IF is num1 < num2 (as per the text). Wait, initial num1=6, num2=4, num3=10. First IF: num1 < num2? 6 < 4? No, so ELSE: num1 = num2 (4). Then the next IF: num2 > num1? 4 > 4? No, so no change. Then sum = 4 + 4 + 10 = 18? But the options: A.12, B.14, C.16, D.18? Wait, maybe I misread the IF conditions. Wait, maybe the first IF is num1 < num3? Let's re-express. Alternatively, maybe the first IF is num1 < num2, then ELSE num1 = num3? No, the text says "ELSE num1 = num2". Wait, maybe the second IF is num2 > num3? No, the text says "num2 > num1". Wait, let's do step by step:

1. num1 = 6, num2 = 4, num3 = 10
2. First IF: num1 < num2? 6 < 4? False → ELSE: num1 = num2 → num1 = 4
3. Second IF: num2 > num1? 4 > 4? False → no change
4. sum = num1 + num2 + num3 = 4 + 4 + 10 = 18

So the answer should be D. 18.

Answer:

D. 18