QUESTION IMAGE
Question
31.) $\triangle fgh$ is an equilateral triangle with $fg = x + 8$, $gh = 2x - 7$, and $fh = 3x - 22$.
$x = \underline{\quad\quad\quad}$ $fg = \underline{\quad\quad\quad}$ $gh = \underline{\quad\quad\quad}$ $fh = \underline{\quad\quad\quad}$
32.) $\triangle lmn$ is an isosceles triangle, with legs $lm$ and $ln$, $lm = 3x - 2$, $ln = 2x + 1$, and $mn = 5x - 2$.
$x = \underline{\quad\quad\quad}$ $lm = \underline{\quad\quad\quad}$ $ln = \underline{\quad\quad\quad}$ $mn = \underline{\quad\quad\quad}$
33.) $\triangle abc$ is an isosceles triangle, with legs $ab$ and $ac$, $ab = 4x - 3$, $bc = x + 9$, and $ac = 6x - 7$.
$x = \underline{\quad\quad\quad}$ $ab = \underline{\quad\quad\quad}$ $ac = \underline{\quad\quad\quad}$ $bc = \underline{\quad\quad\quad}$
Problem 31:
Step1: Set FG = GH (equilateral triangle)
In an equilateral triangle, all sides are equal. So, set \( FG = GH \):
\( x + 8 = 2x - 7 \)
Step2: Solve for x
Subtract \( x \) from both sides: \( 8 = x - 7 \)
Add 7 to both sides: \( x = 15 \)
Step3: Find FG, GH, FH
- \( FG = x + 8 = 15 + 8 = 23 \)
- \( GH = 2x - 7 = 2(15) - 7 = 23 \)
- \( FH = 3x - 22 = 3(15) - 22 = 23 \)
Problem 32:
Step1: Set LM = LN (isosceles legs)
In an isosceles triangle, legs \( LM \) and \( LN \) are equal. So, set \( LM = LN \):
\( 3x - 2 = 2x + 1 \)
Step2: Solve for x
Subtract \( 2x \) from both sides: \( x - 2 = 1 \)
Add 2 to both sides: \( x = 3 \)
Step3: Find LM, LN, MN
- \( LM = 3x - 2 = 3(3) - 2 = 7 \)
- \( LN = 2x + 1 = 2(3) + 1 = 7 \)
- \( MN = 5x - 2 = 5(3) - 2 = 13 \)
Problem 33:
Step1: Set AB = AC (isosceles legs)
In an isosceles triangle, legs \( AB \) and \( AC \) are equal. So, set \( AB = AC \):
\( 4x - 3 = 6x - 7 \)
Step2: Solve for x
Subtract \( 4x \) from both sides: \( -3 = 2x - 7 \)
Add 7 to both sides: \( 4 = 2x \)
Divide by 2: \( x = 2 \)
Step3: Find AB, AC, BC
- \( AB = 4x - 3 = 4(2) - 3 = 5 \)
- \( AC = 6x - 7 = 6(2) - 7 = 5 \)
- \( BC = x + 9 = 2 + 9 = 11 \)
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s:
Problem 31:
\( x = \boldsymbol{15} \), \( FG = \boldsymbol{23} \), \( GH = \boldsymbol{23} \), \( FH = \boldsymbol{23} \)
Problem 32:
\( x = \boldsymbol{3} \), \( LM = \boldsymbol{7} \), \( LN = \boldsymbol{7} \), \( MN = \boldsymbol{13} \)
Problem 33:
\( x = \boldsymbol{2} \), \( AB = \boldsymbol{5} \), \( AC = \boldsymbol{5} \), \( BC = \boldsymbol{11} \)