Question

x = 2y - 15
x =

y =

show calculation

Explanation:

Step1: Analyze the equation

The given equation is \( x = 2y - 15 \). This is a linear equation with two variables, \( x \) and \( y \). To find specific values for \( x \) and \( y \), we need another equation (since we have two variables, we need a system of equations). But if we assume we can express \( y \) in terms of \( x \) or vice - versa, let's solve for \( y \) in terms of \( x \).

Step2: Solve for \( y \)

Starting with \( x = 2y-15 \).
Add 15 to both sides of the equation: \( x + 15=2y-15 + 15\), which simplifies to \( x + 15 = 2y \).
Then divide both sides by 2: \( y=\frac{x + 15}{2}=\frac{1}{2}x+\frac{15}{2}\)

If we assume a value for \( x \), we can find \( y \), or vice - versa. For example, if we take \( x = 1\):

Step3: Substitute \( x = 1 \) into the equation for \( y \)

\( y=\frac{1 + 15}{2}=\frac{16}{2}=8 \)

Or if we take \( y = 10 \):

Step4: Substitute \( y = 10 \) into the equation for \( x \)

\( x=2\times10 - 15=20 - 15 = 5 \)

But since the problem seems to be incomplete (maybe a system of equations is missing), if we assume that this is part of a system and we made a mistake in the problem presentation, but if we just want to express \( x \) and \( y \) in terms of each other:

\( x = 2y-15 \) (this is the expression for \( x \) in terms of \( y \))

And \( y=\frac{x + 15}{2}\) (this is the expression for \( y \) in terms of \( x \))

If we assume that there was a missing equation, for example, if we had another equation like \( x + y=10 \) (a common case), let's solve the system:

We have the system:
\(

$$\begin{cases}x = 2y-15\\x + y=10\end{cases}$$

\)

Substitute \( x = 2y - 15 \) into \( x + y=10 \):

\(2y-15 + y=10\)

Combine like terms: \(3y-15 = 10\)

Add 15 to both sides: \(3y=10 + 15=25\)

\(y=\frac{25}{3}\approx8.33\)

Then \( x=2\times\frac{25}{3}-15=\frac{50}{3}-15=\frac{50 - 45}{3}=\frac{5}{3}\approx1.67\)

But since the problem as presented has only one equation, we can express \( x \) and \( y \) as:

\( x = 2y-15 \)

\( y=\frac{x + 15}{2}\)

If we assume that the user made a mistake and the equation is part of a system where, for example, the other equation is \( x - y=- 5\) (let's check):

System:
\(

$$\begin{cases}x = 2y-15\\x - y=-5\end{cases}$$

\)

Substitute \( x = 2y-15 \) into \( x - y=-5 \):

\(2y-15-y=-5\)

\(y-15=-5\)

\(y=-5 + 15 = 10\)

Then \( x=2\times10-15 = 5\)

So in this case, \( x = 5 \) and \( y = 10 \)

Answer:

If we assume the system \(

$$\begin{cases}x = 2y-15\\x - y=-5\end{cases}$$

\), then \(x = 5\) and \(y = 10\) (answers may vary depending on the complete problem, but since the problem is incomplete, this is a possible solution based on a common system of linear equations)