Question

8 2x - 2y + 5 = 0

Explanation:

Step1: Convert to slope - intercept form ($y = mx + b$)

Starting with \(2x-2y + 5=0\).
First, isolate \(y\):
\(-2y=-2x - 5\).
Then divide each term by \(-2\):
\(y=x+\frac{5}{2}\).

Step2: Find two points

• When \(x = 0\):

\(y=0+\frac{5}{2}=2.5\). So one point is \((0,2.5)\).

• When \(y = 0\):

\(0=x+\frac{5}{2}\), then \(x=-\frac{5}{2}=-2.5\). So another point is \((-2.5,0)\).

Step3: Plot the points and draw the line

Plot \((0,2.5)\) (2.5 units up on the \(y\) - axis) and \((-2.5,0)\) (2.5 units to the left on the \(x\) - axis). Then draw a straight line passing through these two points.

Answer:

Plot the points \((0,2.5)\) and \((-2.5,0)\) and draw a straight line through them to graph the equation \(2x - 2y+5 = 0\).