Question

28 = 2(3z + 4) + 6z

Explanation:

Step1: Expand the bracket

Using the distributive property \(a(b + c)=ab+ac\), we expand \(2(3z + 4)\) to get \(2\times3z+2\times4 = 6z + 8\). So the equation becomes \(28=6z + 8+6z\).

Step2: Combine like terms

Combine the \(z\) terms: \(6z+6z = 12z\). The equation is now \(28 = 12z+8\).

Step3: Subtract 8 from both sides

Subtract 8 from each side: \(28 - 8=12z+8 - 8\), which simplifies to \(20 = 12z\).

Step4: Solve for z

Divide both sides by 12: \(z=\frac{20}{12}=\frac{5}{3}\).

Answer:

\(z = \frac{5}{3}\)