Question

1. $2x - 8y = -4$

$x - 8y = 6$

1. $8x + 3y = 20$

$4x + 3y = 4$

1. $-5x - 6y = 1$

$-5x - y = 21$

1. $-2x + 2y = -12$

$-2x + 2y = -12$

1. $3x - 5y = -21$

$-6x - 6y = -6$

1. $8x - 2y = 18$

$-4x - y = -7$

1. $12x + 3y = -27$

$6x + y = -13$

1. $12x + 3y = 24$

$3x - y = 13$

1. $-90x + 10y = -23$

$54x - 6y = 12$

1. $5x + 5y = -25$

$-4x + 8y = -28$

Explanation:

To solve these systems of linear equations, we can use methods like elimination or substitution. Let's solve problem 28 as an example:

Problem 28: \(

$$\begin{cases} 2x - 8y = -4 \\ x - 8y = 6 \end{cases}$$

\)

Step 1: Eliminate \( y \)

Subtract the second equation from the first equation:

$$
LATEXBLOCK1
$$

Step 2: Substitute \( x = -10 \) into the second equation

$$
LATEXBLOCK2
$$

Final Answer for Problem 28:

The solution is \( x = -10 \) and \( y = -2 \).

We can solve the other problems similarly using elimination or substitution. For example, let's solve problem 29:

Problem 29: \(

$$\begin{cases} 8x + 3y = 20 \\ 4x + 3y = 4 \end{cases}$$

\)

Step 1: Eliminate \( y \)

Subtract the second equation from the first equation:

$$
LATEXBLOCK4
$$

Step 2: Substitute \( x = 4 \) into the second equation

$$
LATEXBLOCK5
$$

Final Answer for Problem 29:

The solution is \( x = 4 \) and \( y = -4 \).

We can continue this process for the remaining problems. If you need help with a specific problem, please let me know!

Answer:

To solve these systems of linear equations, we can use methods like elimination or substitution. Let's solve problem 28 as an example:

Problem 28: \(

$$\begin{cases} 2x - 8y = -4 \\ x - 8y = 6 \end{cases}$$

\)

Step 1: Eliminate \( y \)

Subtract the second equation from the first equation:

$$
LATEXBLOCK1
$$

Step 2: Substitute \( x = -10 \) into the second equation

$$
LATEXBLOCK2
$$

Final Answer for Problem 28:

The solution is \( x = -10 \) and \( y = -2 \).

We can solve the other problems similarly using elimination or substitution. For example, let's solve problem 29:

Problem 29: \(

$$\begin{cases} 8x + 3y = 20 \\ 4x + 3y = 4 \end{cases}$$

\)

Step 1: Eliminate \( y \)

Subtract the second equation from the first equation:

$$
LATEXBLOCK4
$$

Step 2: Substitute \( x = 4 \) into the second equation

$$
LATEXBLOCK5
$$

Final Answer for Problem 29:

The solution is \( x = 4 \) and \( y = -4 \).

We can continue this process for the remaining problems. If you need help with a specific problem, please let me know!