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Question
- you are given the following ordered pairs. (3.5, -1)(-1.5, 3)(-3, 3)(3.5, 2.5)(-1.5, -1.5) part a graph the ordered pairs on the coordinate plane. part b find the two ordered pairs on the coordinate plane that are 4.5 units apart. 104 2 - 5 find distances on the coordinate plane
Step1: Recall the distance formula
The distance formula between two points \((x_1,y_1)\) and \((x_2,y_2)\) is \(d=\sqrt{(x_2 - x_1)^2+(y_2 - y_1)^2}\).
Step2: Check each pair of points
For the points \((3.5,-1)\) and \((3.5,2.5)\):
Here \(x_1 = 3.5,y_1=-1,x_2 = 3.5,y_2 = 2.5\)
For the points \((3.5,-1)\) and \((-1.5,3)\):
For the points \((3.5,-1)\) and \((-3,3)\):
For the points \((3.5,-1)\) and \((-1.5,-1.5)\):
For the points \((-1.5,3)\) and \((-3,3)\):
Here \(y_1 = 3,y_2 = 3\)
For the points \((-1.5,3)\) and \((3.5,2.5)\):
For the points \((-1.5,3)\) and \((-1.5,-1.5)\):
Here \(x_1=-1.5,x_2=-1.5\)
For the points \((-3,3)\) and \((3.5,2.5)\):
For the points \((-3,3)\) and \((-1.5,-1.5)\):
For the points \((3.5,2.5)\) and \((-1.5,-1.5)\):
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The two ordered pairs \((-1.5,3)\) and \((-1.5,-1.5)\) are \(4.5\) units apart.