Question

a 0.25 kg phone falls from a ledge. at 0.6 s, the velocity of the phone is 6.0 m/s. what is the kinetic energy of the phone? $e_k = ? j$ $e_k = \frac{1}{2}mv^2$ 4.5 j 2.3 j 50 j

Explanation:

Step1: Identify given values

Mass \( m = 0.25 \, \text{kg} \), velocity \( v = 6.0 \, \text{m/s} \), and the formula for kinetic energy \( E_K=\frac{1}{2}mv^2 \).

Step2: Substitute values into the formula

Substitute \( m = 0.25 \) and \( v = 6.0 \) into \( E_K=\frac{1}{2}mv^2 \):

$$ E_K=\frac{1}{2} \times 0.25 \times (6.0)^2 $$

Step3: Calculate the value

First, calculate \( (6.0)^2 = 36 \). Then, \( \frac{1}{2} \times 0.25 = 0.125 \). Multiply these results: \( 0.125 \times 36 = 4.5 \).

Answer:

4.5 J