Question

24 a large firework is launched upward, in a straight line. it travels upward for 126 meters, with an average velocity of 36 m/s. how long did it take the firework to travel this distance? 90 seconds 5.6 seconds 3.5 seconds 2.0 seconds

Explanation:

Step1: Recall the formula for velocity

The formula for average velocity \(v=\frac{d}{t}\), where \(d\) is distance and \(t\) is time. We need to solve for \(t\), so we can rewrite the formula as \(t = \frac{d}{v}\).

Step2: Substitute the given values

We are given that \(d = 126\) meters and \(v=36\) m/s. Substituting these values into the formula \(t=\frac{d}{v}\), we get \(t=\frac{126}{36}\).

Step3: Calculate the value of \(t\)

\(\frac{126}{36}=\frac{126\div18}{36\div18}=\frac{7}{2}=3.5\)

Answer:

3.5 seconds