Question

212 83bi → a zx + 4 2he
in the above equation solve for a,z, and x.

Explanation:

Step1: Calculate mass number \(A\)

In a nuclear reaction, the sum of mass numbers on both sides is equal. So, \(212=A + 4\). Solving for \(A\), we get \(A=212 - 4=208\).

Step2: Calculate atomic number \(Z\)

The sum of atomic numbers on both sides is equal. So, \(83=Z + 2\). Solving for \(Z\), we get \(Z=83 - 2 = 81\).

Step3: Identify element \(X\)

Looking at the periodic table, the element with atomic number \(Z = 81\) is Thallium (\(Tl\)).

Answer:

\(A = 208\), \(Z = 81\), \(X=Tl\)