Question

21 a flowerpot falls 25.0m towards a pedestrian. how long does the pedestrian have to move out of the way? (write your answer in 3 significant figures)

Explanation:

Step1: Identify the kinematic equation

The kinematic equation for free - fall motion is \(h = v_0t+\frac{1}{2}gt^{2}\). Since the flowerpot is dropped (\(v_0 = 0\)), the equation simplifies to \(h=\frac{1}{2}gt^{2}\).

Step2: Solve for \(t\)

From \(h=\frac{1}{2}gt^{2}\), we can express \(t\) as \(t=\sqrt{\frac{2h}{g}}\). Given \(h = 25.0\ m\) and \(g = 9.8\ m/s^{2}\), substitute these values into the formula:

$$t=\sqrt{\frac{2\times25.0}{9.8}}$$

$$t=\sqrt{\frac{50}{9.8}}$$

$$t=\sqrt{5.102}$$

$$t\approx2.26\ s$$

Answer:

\(2.26\ s\)