# Explicación: ## Paso 1: Definir el triángulo para el problema 3 El tablero es la hipotenusa ($c=10$ pies), la distancia desde la base del muro es un cateto ($a=6$ pies). Usamos …
El tablero es la hipotenusa ($c=10$ pies), la distancia desde la base del muro es un cateto ($a=6$ pies). Usamos el teorema de Pitágoras $c^2=a^2+b^2$ para encontrar la altura $b$.
$$10^2 = 6^2 + b^2$$
Despejar $b$ y resolver:
$$b = \sqrt{10^2 - 6^2} = \sqrt{100 - 36} = \sqrt{64} = 8$$
Los recorridos forman catetos: $a=1$ milla (norte), $b=2$ millas (este). La ruta directa es la hipotenusa $c$.
$$c^2 = 1^2 + 2^2$$
Resolver y redondear al décimo más cercano:
$$c = \sqrt{1^2 + 2^2} = \sqrt{1 + 4} = \sqrt{5} \approx 2.2$$
El tablero es la hipotenusa ($c=10$ pies), la distancia desde la base del muro es un cateto ($a=6$ pies). Usamos el teorema de Pitágoras $c^2=a^2+b^2$ para encontrar la altura $b$.
$$10^2 = 6^2 + b^2$$
Despejar $b$ y resolver:
$$b = \sqrt{10^2 - 6^2} = \sqrt{100 - 36} = \sqrt{64} = 8$$
Los recorridos forman catetos: $a=1$ milla (norte), $b=2$ millas (este). La ruta directa es la hipotenusa $c$.
$$c^2 = 1^2 + 2^2$$
Resolver y redondear al décimo más cercano:
$$c = \sqrt{1^2 + 2^2} = \sqrt{1 + 4} = \sqrt{5} \approx 2.2$$
El tablero es la hipotenusa ($c=10$ pies), la distancia desde la base del muro es un cateto ($a=6$ pies). Usamos el teorema de Pitágoras $c^2=a^2+b^2$ para encontrar la altura $b$.
$$10^2 = 6^2 + b^2$$
Despejar $b$ y resolver:
$$b = \sqrt{10^2 - 6^2} = \sqrt{100 - 36} = \sqrt{64} = 8$$
Los recorridos forman catetos: $a=1$ milla (norte), $b=2$ millas (este). La ruta directa es la hipotenusa $c$.
$$c^2 = 1^2 + 2^2$$
Resolver y redondear al décimo más cercano:
$$c = \sqrt{1^2 + 2^2} = \sqrt{1 + 4} = \sqrt{5} \approx 2.2$$
3. jovan is building a fort in his backyard using a 10 - foot board. he leans the base of the board 6 feet away from the base of the wall. how high will the board be able to reach up the wall? if necessary, round to the nearest tenth. 4. alpia biked 1 mile north from her home to the museum. she then biked 2 miles east from the museum to her friend’s house. how far will she bike in miles if she bikes home from her friend’s house in a straight line? if necessary, round to the nearest tenth.
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