I’ll call it a day
\( x = \frac{4}{3} \) ### Turn 2 Answer # Knowledge Points: - Solving linear equations with one variable. - Using inverse operations (multiplication, subtraction, division) to iso…
\( x = \frac{4}{3} \) ### Turn 2 Answer # Knowledge Points: - Solving linear equations with one variable. - Using inverse operations (multiplication, subtraction, division) to iso…
$9 = \\frac{1}{2}(9x + 6)$
Send a few similar problems
1.x=9
Yes
I’ll do B
The answer is x=3.5
I’ll try a third one
The answer is 2
I’ll call it a day
$9 = \\frac{1}{2}(9x + 6)$
Send a few similar problems
1.x=9
Yes
I’ll do B
The answer is x=3.5
I’ll try a third one
The answer is 2
I’ll call it a day
To eliminate the fraction, multiply each side of the equation \( 9 = \frac{1}{2}(9x + 6) \) by 2.
\[
2\times9 = 2\times\frac{1}{2}(9x + 6)
\]
Simplifying both sides gives:
\[
18 = 9x + 6
\]
Subtract 6 from each side of the equation \( 18 = 9x + 6 \) to isolate the term with \( x \).
\[
18 - 6 = 9x + 6 - 6
\]
Simplifying both sides gives:
\[
12 = 9x
\]
Divide each side of the equation \( 12 = 9x \) by 9 to solve for \( x \).
\[
x = \frac{12}{9}
\]
Simplify the fraction \( \frac{12}{9} \) by dividing the numerator and denominator by their greatest common divisor, which is 3.
\[
x = \frac{4}{3}
\]
\( x = \frac{4}{3} \)
Nice job getting that first one! Let me check—wait, hold on, let's walk through it quick to make sure. Starting with 8 = 1/3(6x + 9), multiply both sides by 3 first: 24 = 6x + 9. Then subtract 9: 15 = 6x. Divide by 6, and simplify 15/6 to 5/2 (or 2.5). Oops, looks like you might have made a tiny misstep! No worries though, algebra can be tricky. Wanna try again or move to the next one?
Alright, let's give that first one another go, or jump straight to problem 2—your call! 😊
A. Retry problem 1: \( 8=\frac{1}{3}(6x + 9) \)
B. Move to problem 2: \( 10=\frac{1}{4}(8x + 12) \)
Awesome, let's tackle problem 2: \( 10=\frac{1}{4}(8x + 12) \)
Take it step by step—you got this!
Perfect! That's exactly right (and if we want to write it as a fraction, it's 7/2, but 3.5 works too). Great job breaking it down 😎 Wanna try the third one now, or take a quick break?
Let's go for it! Problem 3 is: \( 7=\frac{1}{5}(10x + 15) \)
You've been crushing these, I know you've got this!
YES, that's 100% correct! 🎉 You totally nailed all these—great work with the fractions and isolating x. Wanna do a couple more for extra practice, or call it a win for today?
Smart move—you earned that break! 🎊 Great job working through those equations today, you’re really getting the hang of this. Catch you next time!
To eliminate the fraction, multiply each side of the equation \( 9 = \frac{1}{2}(9x + 6) \) by 2.
\[
2\times9 = 2\times\frac{1}{2}(9x + 6)
\]
Simplifying both sides gives:
\[
18 = 9x + 6
\]
Subtract 6 from each side of the equation \( 18 = 9x + 6 \) to isolate the term with \( x \).
\[
18 - 6 = 9x + 6 - 6
\]
Simplifying both sides gives:
\[
12 = 9x
\]
Divide each side of the equation \( 12 = 9x \) by 9 to solve for \( x \).
\[
x = \frac{12}{9}
\]
Simplify the fraction \( \frac{12}{9} \) by dividing the numerator and denominator by their greatest common divisor, which is 3.
\[
x = \frac{4}{3}
\]
\( x = \frac{4}{3} \)
Nice job getting that first one! Let me check—wait, hold on, let's walk through it quick to make sure. Starting with 8 = 1/3(6x + 9), multiply both sides by 3 first: 24 = 6x + 9. Then subtract 9: 15 = 6x. Divide by 6, and simplify 15/6 to 5/2 (or 2.5). Oops, looks like you might have made a tiny misstep! No worries though, algebra can be tricky. Wanna try again or move to the next one?
Alright, let's give that first one another go, or jump straight to problem 2—your call! 😊
A. Retry problem 1: \( 8=\frac{1}{3}(6x + 9) \)
B. Move to problem 2: \( 10=\frac{1}{4}(8x + 12) \)
Awesome, let's tackle problem 2: \( 10=\frac{1}{4}(8x + 12) \)
Take it step by step—you got this!
Perfect! That's exactly right (and if we want to write it as a fraction, it's 7/2, but 3.5 works too). Great job breaking it down 😎 Wanna try the third one now, or take a quick break?
Let's go for it! Problem 3 is: \( 7=\frac{1}{5}(10x + 15) \)
You've been crushing these, I know you've got this!
YES, that's 100% correct! 🎉 You totally nailed all these—great work with the fractions and isolating x. Wanna do a couple more for extra practice, or call it a win for today?
Smart move—you earned that break! 🎊 Great job working through those equations today, you’re really getting the hang of this. Catch you next time!
I’ll call it a day
Top-left cell: 180 Top-right cell: 6 Bottom-left cell: 600 Bottom-right cell: 20 Final product: 806
| Equation | Solution (Fraction) | Solution (Decimal) | |----------|---------------------|--------------------| | $2x=3$ | $\frac{3}{2}$ | $1.5$ | | $5y=3$ | $\frac{3}{5}$ | $0.6$…
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\(-15\)
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The equation is \( 6 + 29.25x = 357 \), and the number of people \( x = 12 \).
Oh, I get why you might be asking that—withdrawal from any substance can feel really disorienting. From what I’ve heard, common stuff includes irritability, trouble sleeping (like…
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