Question

1. order the cyclists from fastest to slowest. three cyclists start a bike race. they race 6 s.

Explanation:

Step1: Recall speed - distance relationship

Speed is distance divided by time. For a fixed - time interval, the cyclist who travels the greatest distance is the fastest.

Step2: Determine distances at \(t = 6s\)

From the graph, at \(t = 6s\), cyclist A has traveled 16 units of distance, cyclist B has traveled 16 units of distance (same as A at \(t = 6s\)), and cyclist C has traveled 8 units of distance.

Step3: Compare speeds

Since speed \(v=\frac{d}{t}\) and \(t\) is the same (\(t = 6s\)) for all cyclists, we compare the distances \(d\). The greater the \(d\), the greater the \(v\). Cyclist A and B have the same distance traveled at \(t = 6s\) and more than cyclist C. Also, looking at the slopes of the lines (rate of change of distance with respect to time), cyclist B has a steeper slope after \(t = 3s\) compared to A. So the order from fastest to slowest is B, A, C.

Answer:

B, A, C