Question

1st semester exam
simplify: -10b(1 + 2b) – 7b(1 + 3b) desmos
○ - 41b²- 17b
○ -41b²- 10b
○ -41b²- 3b
○ -6 + 50b -8b²

Explanation:

Step1: Distribute the terms

First, distribute \(-10b\) in \(-10b(1 + 2b)\) and \(-7b\) in \(-7b(1 + 3b)\).
For \(-10b(1 + 2b)\), we get \(-10b\times1 + (-10b)\times2b = -10b - 20b^2\).
For \(-7b(1 + 3b)\), we get \(-7b\times1 + (-7b)\times3b = -7b - 21b^2\).
So the expression becomes \(-10b - 20b^2 - 7b - 21b^2\).

Step2: Combine like terms

Combine the \(b^2\) terms and the \(b\) terms.
For \(b^2\) terms: \(-20b^2 - 21b^2 = -41b^2\).
For \(b\) terms: \(-10b - 7b = -17b\).
Putting them together, we have \(-41b^2 - 17b\).

Answer:

\(-41b^2 - 17b\) (corresponding to the first option: \(-41b^2 - 17b\))