Question

8 a 1910 kg truck pushes on the road with a force of 9560 n. what is the acceleration of the truck?
21.4 m/s²
0.137 m/s²
5.01 m/s²
10.3 m/s²

Explanation:

Step1: Apply Newton's third law

According to Newton's third law, the force exerted by the road on the truck \(F = 9560\ N\) (equal in magnitude to the force the truck exerts on the road).

Step2: Use Newton's second law \(F = ma\)

We know \(m=1910\ kg\) and \(F = 9560\ N\). Rearranging \(F = ma\) for \(a\), we get \(a=\frac{F}{m}\).
Substitute the values: \(a=\frac{9560}{1910}\)

$$a=\frac{9560}{1910}\approx5.01\ m/s^{2}$$

Answer:

\(5.01\ m/s^{2}\) (the third option)