Question

1. a square has an area of $81in^{2}$. what is the perimeter of the square?

36 in
18 in
12 in
256 in

Explanation:

Step1: Find the side length of the square

The area formula of a square is \(A = s^{2}\), where \(A\) is the area and \(s\) is the side - length. Given \(A = 81\space in^{2}\), then \(s=\sqrt{A}\). So \(s=\sqrt{81}=9\space in\).

Step2: Calculate the perimeter of the square

The perimeter formula of a square is \(P = 4s\). Substitute \(s = 9\space in\) into the formula, we get \(P=4\times9 = 36\space in\).

Answer:

36 in