Question

1. a 12 kg sled experiences 30 n of pulling force and 6 n of friction. what is its acceleration?
2. a 1,000 kg car accelerates at 3 m/s². what is the net force acting on it?
3. a 0.3 kg tennis ball experiences a 1.2 n net force. find its acceleration.
4. a 5 kg block slides on a surface with 2 n friction. a 15 n horizontal force is applied. what is its acceleration?
5. a 50 kg student jumps and accelerates upward at 1.5 m/s². find the net force acting on the student.
6. a 25 kg object is pulled with 100 n of force. if friction is 25 n, what is its acceleration?
7. a 10 kg box on a smooth floor is pushed with 40 n. what is the acceleration?

Explanation:

Step1: Determine the net force

According to Newton's second law \(F = ma\), where \(F\) is the net force, \(m\) is the mass, and \(a\) is the acceleration. For problems with friction, the net force \(F_{net}=F_{applied}-F_{friction}\).

Step2: Calculate the acceleration

Rearrange the formula \(a=\frac{F_{net}}{m}\) to find the acceleration.

Problem 17

• Step1: Calculate net force

\(F_{net}=30 - 6=24\space N\)

• Step2: Calculate acceleration

\(a=\frac{24}{12}=2\space m/s^{2}\)

Problem 18

• Step1: Use Newton's second law

\(F = ma\), where \(m = 1000\space kg\) and \(a=3\space m/s^{2}\)

• Step2: Calculate force

\(F=1000\times3 = 3000\space N\)

Problem 19

• Step1: Use Newton's second law

\(a=\frac{F}{m}\), where \(F = 1.2\space N\) and \(m=0.3\space kg\)

• Step2: Calculate acceleration

\(a=\frac{1.2}{0.3}=4\space m/s^{2}\)

Problem 20

• Step1: Calculate net force

\(F_{net}=15 - 2=13\space N\)

• Step2: Calculate acceleration

\(a=\frac{13}{5}=2.6\space m/s^{2}\)

Problem 21

• Step1: Use Newton's second law

\(F = ma\), where \(m = 50\space kg\) and \(a=1.5\space m/s^{2}\)

• Step2: Calculate force

\(F=50\times1.5 = 75\space N\)

Problem 22

• Step1: Calculate net force

\(F_{net}=100 - 25=75\space N\)

• Step2: Calculate acceleration

\(a=\frac{75}{25}=3\space m/s^{2}\)

Problem 23

• Step1: Use Newton's second law

\(a=\frac{F}{m}\), where \(F = 40\space N\) and \(m=10\space kg\)

• Step2: Calculate acceleration

\(a=\frac{40}{10}=4\space m/s^{2}\)

Answer:

1. \(2\space m/s^{2}\)
2. \(3000\space N\)
3. \(4\space m/s^{2}\)
4. \(2.6\space m/s^{2}\)
5. \(75\space N\)
6. \(3\space m/s^{2}\)
7. \(4\space m/s^{2}\)