Question

1. what is the net force applied on the soccer ball? *

5 points
50 n
125 n
200 n
9,375 n

Explanation:

Step1: Determine the direction of forces

Forces are in opposite directions. Let the right - ward force \(F_1 = 75N\) and the left - ward force \(F_2=125N\).

Step2: Calculate the net force

The formula for net force when forces are in opposite directions is \(F_{net}=\vert F_1 - F_2\vert\). Substitute \(F_1 = 75N\) and \(F_2 = 125N\) into the formula: \(F_{net}=\vert75 - 125\vert=\vert- 50\vert = 50N\). The direction is towards the larger force (left - ward in this case, but the magnitude is what's asked for).

Answer:

50 N