Question

a 150 - watt lightbulb is brighter than a 60. - watt lightbulb when both are operating at a potential difference of 110 volts. compared to the resistance
more resistance and draws less current
less resistance and draws less current
more resistance and draws more current
less resistance and draws more current

Explanation:

Step1: Calculate current using \(P = UI\)

For the 150 - watt bulb: \(I_1=\frac{P_1}{U}=\frac{150}{110}\approx1.36\space A\)
For the 60 - watt bulb: \(I_2=\frac{P_2}{U}=\frac{60}{110}\approx0.55\space A\)

Step2: Calculate resistance using \(R=\frac{U}{I}\)

For the 150 - watt bulb: \(R_1=\frac{U}{I_1}=\frac{110}{1.36}\approx80.9\space\Omega\)
For the 60 - watt bulb: \(R_2=\frac{U}{I_2}=\frac{110}{0.55} = 200\space\Omega\)

Answer:

The 150 - watt bulb has less resistance and draws more current. So the answer is the fourth option: less resistance and draws more current.