Question

15 starting from rest, a car undergoes a constant acceleration of 5 m/s². how far will the car travel in 1.5 seconds? (write your answer in 2 significant figures)

Explanation:

Step1: Identify the kinematic equation

Since the car starts from rest ($u = 0$), we use the equation $s=ut+\frac{1}{2}at^{2}$.

Step2: Substitute the values

Here, $u = 0$, $a = 5\ m/s^{2}$, and $t = 1.5\ s$.
Substituting into the equation: $s=(0\times1.5)+\frac{1}{2}\times5\times(1.5)^{2}$.
First, calculate $(1.5)^{2}=2.25$.
Then, $\frac{1}{2}\times5\times2.25=\frac{11.25}{2}=5.625$.

Step3: Round to 2 significant figures

$5.625\approx5.6$ (when rounded to 2 significant figures).

Answer:

$5.6\ m$