Question

1. -/1 pointscalculate the speed of a satellite moving in a circular orbit about the earth at a height of 2900×10³ m. the mass of the earth is 5.98×10²⁴ kg and the mass of the satellite is1400 kg. m/s16. -/2 pointsdetails my notes ask your teacheran asteroid and a comet collide head on. prior to the collision, the asteroid has a momentum of 700,000 kg·m/s up and the comet has a momentum of 800,000kg·m/s down. after the collision the asteroid has a momentum of 650,000 kg·m/s up. after the collision, what is the comets momentum?kg·m/s

Explanation:

Step1: Apply conservation of momentum

The total momentum before collision is equal to the total momentum after collision. Let \(p_{a1}\) be the asteroid's initial momentum, \(p_{c1}\) be the comet's initial momentum, \(p_{a2}\) be the asteroid's final momentum, and \(p_{c2}\) be the comet's final momentum. So \(p_{a1}+p_{c1}=p_{a2}+p_{c2}\).

Step2: Rearrange the formula to find \(p_{c2}\)

We can rewrite the formula as \(p_{c2}=p_{a1}+p_{c1}-p_{a2}\). Given \(p_{a1} = 700000\space kg\cdot m/s\) (up), \(p_{c1}=800000\space kg\cdot m/s\) (down, so \(p_{c1}=- 800000\space kg\cdot m/s\) if up is positive), \(p_{a2}=650000\space kg\cdot m/s\) (up). Then \(p_{c2}=700000+( - 800000)-650000\).

Step3: Calculate the value

\(p_{c2}=700000 - 800000-650000=-750000\space kg\cdot m/s\) (down)

Answer:

\(750000\space kg\cdot m/s\) (down)