Question

140 n of force is applied to a 35 kg block, accelerating it at \\(4\text{ m/s}^2\\). a second 75 kg object is also accelerating at \\(4\text{ m/s}^2\\). how does the force applied to the two blocks compare?

\\(140\text{ n} = 35\text{ kg} (4\frac{\text{m}}{\text{s}^2})\\) \\( ? \text{ n} = 75\text{ kg} (4\frac{\text{m}}{\text{s}^2})\\)

• the force on the 75 kg block is smaller.
• the force on the 75 kg block is larger.
• the force on the 75 kg block is the same as the 35 kg block.

Explanation:

Calculate the force on the second block

$$ F_2 = 75\text{ kg} \times 4\text{ m/s}^2 = 300\text{ N} $$

Compare the forces on the two blocks

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Answer:

• The force on the 75 kg block is smaller.
• The force on the 75 kg block is larger. (Correct answer)
• The force on the 75 kg block is the same as the 35 kg block.