Question

1. ** a photon has a frequency of 5.0 × 10¹⁴ hz. another photon has a frequency of 8.0 × 10¹⁴ hz. which photon has more energy?

Explanation:

Step1: Recall the formula for photon energy

The energy of a photon is given by \(E = h
u\), where \(h = 6.626\times10^{-34}\space J\cdot s\) (Planck's constant) and \(
u\) is the frequency of the photon.

Step2: Analyze the relationship between energy and frequency

Since \(h\) is a constant, \(E\propto
u\) (energy is directly proportional to frequency).

Step3: Compare the frequencies

We have \(
u_1=5.0\times 10^{14}\space Hz\) and \(
u_2 = 8.0\times 10^{14}\space Hz\). Since \(8.0\times 10^{14}>5.0\times 10^{14}\)

Answer:

The photon with a frequency of \(8.0\times 10^{14}\space Hz\) has more energy.