Question

1. calculate the value of x in the triangle below rounded to two decimal places.

Explanation:

Step1: Apply Pythagorean theorem

For a right - triangle, \(a^{2}+b^{2}=c^{2}\), where \(a = 20\), \(b = 26\), and \(c=x\).
So, \(x^{2}=20^{2}+26^{2}\).

Step2: Calculate \(20^{2}\) and \(26^{2}\)

\(20^{2}=400\), \(26^{2}=676\).
Then \(x^{2}=400 + 676=1076\).

Step3: Find \(x\)

\(x=\sqrt{1076}\approx32.8\)

Answer:

\(32.8\)