Question

1. (6)(2) - 2

a) 14 b) 10
c) 8 d) 4

1. (4)(2 + 2) - 1

a) 11 b) 9
c) 15 d) 13

1. ((3)(2)) ÷ (1 + 2)

a) 1 b) 4
c) 2 d) 5

1. x - (2 - y); use x = 5, and y = 1

Explanation:

Problem 2:

Step1: Multiply 6 and 2

$(6)(2) = 12$

Step2: Subtract 2 from the result

$12 - 2 = 10$

Step1: Calculate inside the parentheses

$2 + 2 = 4$

Step2: Multiply 4 and the result

$(4)(4) = 16$

Step3: Subtract 1 from the result

$16 - 1 = 15$

Step1: Multiply 3 and 2

$(3)(2) = 6$

Step2: Calculate inside the denominator parentheses

$1 + 2 = 3$

Step3: Divide the two results

$\frac{6}{3} = 2$

Answer:

B) 10

Problem 4: