Question

14.
-1/3
×
-1/3

Explanation:

Step1: Identify the operation

The problem involves multiplying two fractions: $\frac{1}{3}$ and $\frac{1}{3}$.

Step2: Apply fraction multiplication rule

To multiply two fractions $\frac{a}{b} \times \frac{c}{d}$, we use the rule $\frac{a \times c}{b \times d}$. Here, $a = 1$, $b = 3$, $c = 1$, $d = 3$. So, $\frac{1 \times 1}{3 \times 3} = \frac{1}{9}$. Wait, but there's a 14? Maybe the image is misread. Wait, maybe it's $14\frac{1}{3} \times \frac{1}{3}$? Let's re - examine. If it's a mixed number $14\frac{1}{3}$ (which is $\frac{14\times3 + 1}{3}=\frac{43}{3}$) multiplied by $\frac{1}{3}$. Then $\frac{43}{3} \times \frac{1}{3}=\frac{43}{9}=4\frac{7}{9}$. But the initial image is a bit unclear. Assuming it's $\frac{1}{3} \times \frac{1}{3}$ (maybe the 14 is a typo or misdrawing), the product of $\frac{1}{3}$ and $\frac{1}{3}$ is $\frac{1}{9}$. If it's $14\frac{1}{3} \times \frac{1}{3}$:

Step1: Convert mixed number to improper fraction

$14\frac{1}{3}=\frac{14\times3 + 1}{3}=\frac{43}{3}$

Step2: Multiply the fractions

$\frac{43}{3} \times \frac{1}{3}=\frac{43\times1}{3\times3}=\frac{43}{9}=4\frac{7}{9}$

Answer:

If it's $\frac{1}{3} \times \frac{1}{3}$, the answer is $\frac{1}{9}$. If it's $14\frac{1}{3} \times \frac{1}{3}$, the answer is $\frac{43}{9}$ (or $4\frac{7}{9}$). Given the unclear image, but assuming the intended operation is fraction multiplication of $\frac{1}{3}$ and $\frac{1}{3}$, the answer is $\frac{1}{9}$.