Question

p. 132 draw a spring that has high elastic potential energy and low kinetic energy. at the bottom give a written explanation for your drawing.

Explanation:

Step1: Recall energy - spring concepts

Elastic potential energy in a spring is given by $U = \frac{1}{2}kx^{2}$, where $k$ is the spring - constant and $x$ is the displacement from the equilibrium position. Kinetic energy is $K=\frac{1}{2}mv^{2}$, where $m$ is the mass and $v$ is the velocity. High elastic potential energy means a large displacement $x$ from the equilibrium position. Low kinetic energy means the spring is either at rest ($v = 0$) or moving very slowly.

Step2: Draw the spring

Draw a spring that is either stretched or compressed significantly from its natural length. For example, if it is a vertical spring - mass system, draw the spring stretched downwards a large amount if it is a hanging spring, or if it is a horizontal spring on a frictionless surface, draw it either stretched or compressed by a large distance.

Step3: Provide written explanation

The spring has high elastic potential energy because it is either stretched or compressed a large distance from its equilibrium position. According to the formula $U=\frac{1}{2}kx^{2}$, as $x$ (displacement) increases, the elastic potential energy $U$ increases. The spring has low kinetic energy because it is either at rest (e.g., at the maximum displacement point in a simple - harmonic - motion scenario where the velocity $v = 0$) or moving very slowly.

Answer:

Draw a significantly stretched or compressed spring. Explanation: High elastic potential energy due to large displacement from equilibrium ($U=\frac{1}{2}kx^{2}$, large $x$ means large $U$). Low kinetic energy as it is either at rest or moving slowly.