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13. what results if a black andalusian fowl is crossed with a bluish - …

Question

  1. what results if a black andalusian fowl is crossed with a bluish - gray andalusian fowl?

a. what is the probability that they will be black?______%
b. what is the probability that they will be white?______%
c. what is the probability that they will be bluish - gray?______%

Explanation:

Step1: Determine the genotypes

Let's assume that the allele for black color is \(B\) and for white color is \(b\). In Andalusian fowls, black (\(BB\)) and white (\(bb\)) show incomplete dominance. The bluish - gray color has the genotype \(Bb\). A black fowl has genotype \(BB\) and a bluish - gray fowl has genotype \(Bb\).

Step2: Set up the Punnett square

The cross is \(BB\times Bb\). The gametes from the black fowl (\(BB\)) are all \(B\). The gametes from the bluish - gray fowl (\(Bb\)) are \(B\) and \(b\). The Punnett square is:

\(B\)\(b\)

Step3: Calculate the probabilities

  • For black (\(BB\)): There is \(1\) out of \(2\) possible genotypes (\(BB\) and \(Bb\)). So the probability of \(BB=\frac{1}{2}= 50\%\)
  • For white (\(bb\)): There is \(0\) out of \(2\) possible genotypes that is \(bb\). So the probability of \(bb = 0\%\)
  • For bluish - gray (\(Bb\)): There is \(1\) out of \(2\) possible genotypes (\(BB\) and \(Bb\)). So the probability of \(Bb=\frac{1}{2}=50\%\)

Answer:

a. \(50\%\)
b. \(0\%\)
c. \(50\%\)