Question

13 opción múltiple 1 punto according to the graph above, what is the objects velocity from 18 to 19 seconds? +2.0 m/s -2.0 m/s +4.0 m/s +1.0 m/s

Explanation:

Step1: Recall velocity formula

Velocity \( v \) is the change in position (\( \Delta x \)) over change in time (\( \Delta t \)), so \( v = \frac{\Delta x}{\Delta t} \).

Step2: Determine position at 18s and 19s

From the graph, at \( t = 18 \) s, position \( x_{18} = -2 \) m. At \( t = 19 \) s, position \( x_{19} = 0 \) m.

Step3: Calculate \( \Delta x \) and \( \Delta t \)

\( \Delta x = x_{19} - x_{18} = 0 - (-2) = 2 \) m. \( \Delta t = 19 - 18 = 1 \) s.

Step4: Compute velocity

\( v = \frac{\Delta x}{\Delta t} = \frac{2}{1} = +2.0 \) m/s.

Answer:

+2.0 m/s