Question

1. if the temperature and number of particles of gas in a cylinder do not change, and the volume of the cylinder is reduced by half, the pressure of the gas will be as the original pressure.

Explanation:

Step1: Use Boyle's Law

Boyle's Law states that \(P_1V_1 = P_2V_2\) (where \(P\) is pressure and \(V\) is volume, with temperature \(T\) and amount of gas \(n\) constant).

Step2: Substitute the volume relationship

Let \(V_2=\frac{1}{2}V_1\). Then \(P_1V_1 = P_2\times\frac{1}{2}V_1\).

Step3: Solve for \(P_2\)

Divide both sides of the equation \(P_1V_1 = P_2\times\frac{1}{2}V_1\) by \(V_1\) (since \(V_1
eq0\)), we get \(P_1=\frac{1}{2}P_2\). Then multiply both sides by \(2\), so \(P_2 = 2P_1\).

Answer:

twice