Question

1. a graduated cylinder has 22 ml of water placed in it. an irregularly shaped rock is then placed in the graduated cylinder and the volume of the rock and water in the graduated cylinder now reads 30 ml. the mass of the rock is 24 g. a) find the... graduated cylinder now reads 30 ml. the mass of the rock is 24 g. a) find the... b) find the density of the rock.

Explanation:

Part A: Find the volume of the rock

Step 1: Recall the principle of water displacement

The volume of the rock is equal to the difference between the final volume (water + rock) and the initial volume of water.
Initial volume of water, \( V_{initial} = 22\space mL \)
Final volume (water + rock), \( V_{final} = 30\space mL \)

Step 2: Calculate the volume of the rock

The volume of the rock, \( V_{rock} = V_{final} - V_{initial} \)
\( V_{rock} = 30 - 22 = 8\space mL \) (Since \( 1\space mL = 1\space cm^3 \), the volume of the rock is also \( 8\space cm^3 \))

Step 1: Recall the formula for density

Density, \(
ho = \frac{m}{V} \), where \( m \) is the mass and \( V \) is the volume.

Step 2: Identify the values of mass and volume

Mass of the rock, \( m = 24\space g \)
Volume of the rock (from part A), \( V = 8\space cm^3 \)

Step 3: Calculate the density

\(
ho = \frac{24}{8} = 3\space g/cm^3 \)

Answer:

(A):
The volume of the rock is \( 8\space cm^3 \) (or \( 8\space mL \))

Part B: Find the density of the rock