Question

a 113 kg refrigerator sits at rest where the coefficient of static friction is equal to 0.249.

what is the maximum force acting on the refrigerator due to static friction?

\\(f = ?\text{ n}\\)

Explanation:

🆕 New Concept Discovered: Static Friction
The threshold force needed to start moving an object.

Step 1: Identify given values

Identify the mass \( m \), the coefficient of static friction \( \mu_s \), and the acceleration due to gravity \( g \):

$$ m = 113\text{ kg} $$

$$ \mu_s = 0.249 $$

$$ g \approx 9.8\text{ m/s}^2 $$

Step 2: Calculate the normal force

On a flat surface, the normal force \( F_N \) is equal to the gravitational force acting on the object:

$$ F_N = m \cdot g $$

$$ F_N = 113\text{ kg} \times 9.8\text{ m/s}^2 = 1107.4\text{ N} $$

Step 3: Calculate the maximum static friction force

The maximum force of static friction \( F_{s,\text{max}} \) is given by the formula:

$$ F_{s,\text{max}} = \mu_s \cdot F_N $$

$$ F_{s,\text{max}} = 0.249 \times 1107.4\text{ N} \approx 275.74\text{ N} $$

Rounding to three significant figures (matching the given values):

$$ F \approx 276\text{ N} $$

Answer:

276