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11. water/wastewater treatment a sewer line has a flow rate of 1.25 mgd…

Question

  1. water/wastewater treatment a sewer line has a flow rate of 1.25 mgd (million gallons per day). convert this to cfs (cubic feet per second). (round to two decimal places.)

Explanation:

Step1: Convert gallons to cubic feet

We know that \(1\) gallon \( = 0.133681\) cubic feet.
So, \(1.25\times10^{6}\) gallons \(=1.25\times 10^{6}\times0.133681\) cubic feet.

$$1.25\times 10^{6}\times0.133681 = 167101.25$$

cubic feet.

Step2: Convert days to seconds

We know that \(1\) day \(= 24\times60\times60=86400\) seconds.

Step3: Calculate flow rate in cfs

The flow rate \(Q\) (in cfs) is given by the formula \(Q=\frac{\text{Volume (in cubic feet)}}{\text{Time (in seconds)}}\).

$$Q=\frac{167101.25}{86400}$$
$$Q\approx1.93$$

Answer:

\(1.93\) cfs