Question

1. face color chaz and bev both have homozygous recessive genotypes for their color. chaz b b bev b bb bb b bb bb phenotype probability (%) yellow color: 0% blue color: 100%

Explanation:

Step1: Analyze the Punnett Square

The Punnett square shows that both Chaz and Bev have the genotype \( bb \) (homozygous recessive). When we combine their alleles, all the offspring genotypes are \( bb \).

Step2: Determine Phenotype Probability

Since the genotype \( bb \) corresponds to the blue color (as per the problem's context, and the Punnett square results in all \( bb \) genotypes), we calculate the percentage of blue - colored offspring. There are 4 cells in the Punnett square, and all 4 have the \( bb \) genotype. The probability is calculated as \(\frac{4}{4}\times100\% = 100\%\) for blue color, and 0% for yellow color (since no offspring have a genotype corresponding to yellow color).

Answer:

The phenotype probability for yellow color is \( 0\% \) and for blue color is \( 100\% \) (as shown in the given table, which is consistent with the Punnett square analysis where all offspring have the \( bb \) genotype corresponding to blue color).