Question

1. in cabbage butterflies, white wings (w) are dominant to yellow wings (w). a heterozygous butterfly mates with a butterfly that has yellow wings. complete the punnett square and then list the percentages of the expected genotypes for their offspring. white wings genotype probability (%) yellow wings homozygous dominant: heterozygous: homozygous recessive:

Explanation:

Step1: Determine the genotypes of the parents

A heterozygous butterfly has the genotype \(Ww\) (since it has the dominant phenotype but is not homozygous). A butterfly with yellow wings has the genotype \(ww\) (because yellow wings are recessive, so it must have two recessive alleles).

Step2: Set up the Punnett square

The gametes of the \(Ww\) parent are \(W\) and \(w\). The gametes of the \(ww\) parent are \(w\) and \(w\).

	\(W\)	\(w\)
\(w\)	\(Ww\)	\(ww\)

Step3: Calculate the genotype probabilities

• Homozygous dominant (\(WW\)): There are 0 out of 4 squares with \(WW\), so the probability is \(0\%\)
• Heterozygous (\(Ww\)): There are 2 out of 4 squares with \(Ww\). Using the formula \(\text{Probability}=\frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}}\times100\%\), we have \(\frac{2}{4}\times 100\% = 50\%\)
• Homozygous recessive (\(ww\)): There are 2 out of 4 squares with \(ww\). Using the formula \(\text{Probability}=\frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}}\times100\%\), we have \(\frac{2}{4}\times 100\%=50\%\)

Answer:

Homozygous dominant: \(0\%\)
Heterozygous: \(50\%\)
Homozygous recessive: \(50\%\)