Question

1. andre’s tv has a length of 34 inches, and the diagonal measures 39 inches. what is the height of his tv, to the nearest inch?

Explanation:

Step1: Recall Pythagorean theorem

For a right triangle (TV is rectangular, so diagonal forms right triangle with length and height), \(a^2 + b^2 = c^2\), where \(c\) is diagonal, \(a\) is length, \(b\) is height. Let length \(l = 34\), diagonal \(d = 39\), height \(h\). So \(34^2 + h^2 = 39^2\).

Step2: Solve for \(h^2\)

Calculate \(34^2 = 1156\), \(39^2 = 1521\). Then \(h^2 = 1521 - 1156 = 365\).

Step3: Find \(h\)

Take square root: \(h = \sqrt{365} \approx 19.1\), round to nearest inch is 19.

Answer:

19