Question

10n
10n·m
a c b d
fa 1m 1m 1m
fb

Explanation:

Step1: Sum of vertical forces

For the beam, vertical forces: \( F_A + F_B = 10\,\text{N} \) (since only the 10N downward force and the two upward reactions \( F_A, F_B \)).

Step2: Sum of moments about point A

Taking moments about \( A \): \( (10\,\text{N})(1\,\text{m}) + 10\,\text{N·m} = F_B(2\,\text{m}) \) (clockwise moments: 10N at 1m, 10N·m; counter - clockwise moment: \( F_B \) at 2m from A).
Simplify: \( 10 + 10 = 2F_B \) → \( 20 = 2F_B \) → \( F_B = 10\,\text{N} \).

Step3: Find \( F_A \)

From vertical force equilibrium: \( F_A + 10 = 10 \) → \( F_A = 0\,\text{N} \).

Answer:

\( F_A = 0\,\text{N} \), \( F_B = 10\,\text{N} \)