Question

1. what is printed by the following program if the user enters 1?

num_input = int(input(\enter a number: \))
if num_input % 2 == 0:
print(\even\)
elif num_input % 2 != 0:
print(\odd\)
else:
print(\invalid\)

Explanation:

Step1: Analyze the input

The user enters 1, so num_input = 1.

Step2: Check the first condition

Check if num_input % 2 == 0. For 1, \(1 \% 2 = 1\) (since 1 divided by 2 leaves a remainder of 1), so this condition is false.

Step3: Check the elif condition

Check if num_input % 2 != 0. For 1, \(1 \% 2 = 1\), so \(1
eq 0\), this condition is true. So the code inside this elif block will execute.

Step4: Execute the code in the elif block

The code in the elif block is print("Odd"), so this will be printed.

Answer:

Odd