Question

1. two dogs are fighting over a chew toy. one dog pulls the toy with a force of 41 n in the positive x - direction, while the other dog pulls with a force of 32 n in the negative x - direction. what is the net force on the chew toy?

73 n
9 n

• 9 n
• 73 n

Explanation:

Step1: Define forces

Let \(F_1 = 41\space N\) (positive \(x -\)direction) and \(F_2=- 32\space N\) (negative \(x -\)direction).

Step2: Calculate net force

The net force \(F_{net}=F_1 + F_2\). Substitute the values: \(F_{net}=41+( - 32)\).

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Answer:

9 N