Question

10.7 special segments in circles.pdf
2.
6
9
9
x

Explanation:

Step1: Use the intersecting chords theorem

If two chords intersect in a circle, then the products of the lengths of their segments are equal. So, \(6\times x=9\times9\).

Step2: Solve for \(x\)

From \(6x = 81\), we can find \(x\) by dividing both sides of the equation by \(6\). So, \(x=\frac{81}{6}=\frac{27}{2}=13.5\).

Answer:

\(x = 13.5\)