Question

is (2, 10) a solution to this system of equations?
y = x + 8
y = 10x + 3
yes
no

Explanation:

Step1: Substitute x = 2 into first - equation

Substitute \(x = 2\) into \(y=x + 8\). Then \(y=2 + 8=10\).

Step2: Substitute x = 2 into second - equation

Substitute \(x = 2\) into \(y = 10x+3\). Then \(y=10\times2 + 3=20 + 3=23
eq10\).

Answer:

no