Question

1. -/10 points details my notes ask your teacher practice another use an algebraic approach to solve the problem. aura took three biology exams and has an average score of 88. her second exam score was 6 points better than her first, and her third exam score was 6 points better than her second exam. what were her three exam scores? (lowest score) (highest score) resources ebook

Explanation:

Step1: Define variables

Let the first exam score be \( x \). Then the second score is \( x + 6 \), and the third score is \( (x + 6)+ 6=x + 12 \).

Step2: Use average formula

The average of three scores is \( \frac{x+(x + 6)+(x + 12)}{3}=88 \).

Step3: Solve the equation

Simplify the numerator: \( x+x + 6+x + 12=3x + 18 \).
So, \( \frac{3x + 18}{3}=88 \).
Simplify left - hand side: \( x + 6=88 \).
Subtract 6 from both sides: \( x=88 - 6=82 \).

Step4: Find all scores

First score: \( x = 82 \).
Second score: \( x+6=82 + 6 = 88 \).
Third score: \( x + 12=82+12 = 94 \).

Answer:

Lowest score: \( 82 \)
Middle score: \( 88 \)
Highest score: \( 94 \)