Question

does (8, 10) make the inequality 17x + 3y ≥ 6 true?
yes
no
submit

Explanation:

Step1: Substitute x and y values

Substitute \( x = 8 \) and \( y = 10 \) into the inequality \( 17x + 3y \geq 6 \).

$$ 17(8) + 3(10) $$

Step2: Calculate the left - hand side

First, calculate \( 17\times8 = 136 \) and \( 3\times10 = 30 \). Then add them together:

$$ 136+30=166 $$

Step3: Check the inequality

Now, check if \( 166\geq6 \). Since \( 166 \) is greater than \( 6 \), the inequality holds.

Answer:

yes