Question

a 10 kg box is pulled with a force of 30 n. what is the acceleration of the box? 0.3 m/s² 2 m/s² 3 m/s² 10 m/s²

Explanation:

Step1: Use Newton's second law

Newton's second law is \(F = ma\), where \(F\) is force, \(m\) is mass, and \(a\) is acceleration. We need to solve for \(a\), so the formula becomes \(a=\frac{F}{m}\).

Step2: Substitute the given values

Given \(F = 30\space N\) and \(m = 10\space kg\). Substitute into \(a=\frac{F}{m}\), we get \(a=\frac{30}{10}\).

Step3: Calculate the acceleration

\(\frac{30}{10}=3\space m/s^{2}\)

Answer:

\(3\space m/s^{2}\)