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Question
- evaluate: (5-3)^0 + (3+4)^2 - 5^0
Step1: Simplify exponents with zero power
Any non - zero number to the power of 0 is 1. So, \((5 - 3)^0=2^0 = 1\) and \(5^0 = 1\).
Step2: Simplify the square term
Calculate \((3 + 4)^2\). First, \(3+4 = 7\), then \(7^2=49\).
Step3: Combine the terms
Substitute the simplified values back into the original expression: \(1+49 - 1\). First, \(1+49=50\), then \(50 - 1 = 49\).
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