Question

1. a 1200 kg car travelling at 20.0 m/s speeds up to 30.0 m/s. what is the impulse experienced by the car?

Explanation:

Step1: Recall the impulse - momentum theorem

The impulse - momentum theorem states that \(J=\Delta p\), where \(J\) is the impulse and \(\Delta p\) is the change in momentum. The momentum \(p = mv\), so \(\Delta p=m(v_f - v_i)\)

Step2: Identify the given values

Given \(m = 1200\space kg\), \(v_i=20.0\space m/s\), \(v_f = 30.0\space m/s\)

Step3: Calculate the change in momentum

Substitute the values into the formula \(\Delta p=m(v_f - v_i)\)

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Answer:

\(12000\space kg\cdot m/s\)