QUESTION IMAGE
Question
(a + 1)(a + 2) = 0
a. (1, 2)
b. (2, 1)
c. (-1, -2)
d. (-2, -1)
Step1: Apply Zero-Product Property
The zero - product property states that if \(AB = 0\), then either \(A=0\) or \(B = 0\) (or both). For the equation \((a + 1)(a+2)=0\), we set each factor equal to zero:
- Case 1: \(a + 1=0\). Solving for \(a\), we subtract 1 from both sides of the equation: \(a=- 1\).
- Case 2: \(a + 2=0\). Solving for \(a\), we subtract 2 from both sides of the equation: \(a=-2\).
Step2: Determine the solution set
The solutions of the equation \((a + 1)(a + 2)=0\) are \(a=-1\) and \(a = - 2\). So the solution set is \((-1,-2)\) (the order of the solutions in the set does not matter in terms of the roots of the equation, but when looking at the options, option C is \((-1,-2)\) and option D is \((-2,-1)\). Since we found the roots as \(a=-1\) and \(a=-2\), the set of solutions is \(\{-1,-2\}\) which is represented as the ordered pair (in terms of the options) \((-1,-2)\) in option C.
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C. \((-1, -2)\)