Question

a t t t -1 -1 -1 -1 -1 = 1 1 1 1 1 1 1

Explanation:

Step1: Count the number of -1s and 1s

Left side: 3 yellow rectangles (let each be \( t \)) and 5 pink squares with -1, so total is \( 3t + 5\times(-1) \).
Right side: Count the yellow squares with 1. Top 3 are single, bottom 2 rows have 2 each. So total 3 + 2 + 2 = 7? Wait, no, let's count again. Right side: first column 5 (1,1,1,1,1? Wait no, the right side has: first column 5? Wait no, the right side figure: first column (vertical) has 5? Wait no, the right side: top three are single (1 each), then two rows with two 1s each. So 3 + 2 + 2 = 7? Wait no, let's look at the image again. Left side: 3 yellow rectangles (t) and 5 pink squares (-1). Right side: let's count the number of 1s. The right side has: first column (vertical) 3? No, the right side: top three are stacked (1,1,1), then two rows with two 1s each (so 2 rows × 2 = 4). So total 3 + 4 = 7? Wait, no, the left side: 3t + 5*(-1) = 3t -5. Right side: number of 1s. Let's count the yellow squares: first column (vertical) has 5? Wait no, the right side: top three are 1,1,1 (three), then next two rows (each row has two 1s) so 2 rows × 2 = 4. So total 3 + 4 = 7. So equation: 3t -5 = 7.

Step2: Solve for t

Add 5 to both sides: \( 3t -5 +5 = 7 +5 \) → \( 3t = 12 \).
Divide both sides by 3: \( t = \frac{12}{3} = 4 \). Wait, but maybe I miscounted. Wait left side: 3 t's and 5 (-1)s. Right side: let's count the 1s again. The right side: first column (vertical) has 5? No, the right side figure: top three are 1 (each), then two rows with two 1s (so row 4: two 1s, row 5: two 1s). So total 3 + 2 + 2 = 7. So 3t -5 =7 → 3t=12 → t=4. Wait, but maybe the right side has 7? Wait, let's check again. Left: 3t + 5*(-1) = 3t -5. Right: number of 1s. Let's count the yellow squares: first column (vertical) 5[SSE Completed, Client Connection Error][SSE onError error]

Answer:

Step1: Count the number of -1s and 1s

Left side: 3 yellow rectangles (let each be \( t \)) and 5 pink squares with -1, so total is \( 3t + 5\times(-1) \).
Right side: Count the yellow squares with 1. Top 3 are single, bottom 2 rows have 2 each. So total 3 + 2 + 2 = 7? Wait, no, let's count again. Right side: first column 5 (1,1,1,1,1? Wait no, the right side has: first column 5? Wait no, the right side figure: first column (vertical) has 5? Wait no, the right side: top three are single (1 each), then two rows with two 1s each. So 3 + 2 + 2 = 7? Wait no, let's look at the image again. Left side: 3 yellow rectangles (t) and 5 pink squares (-1). Right side: let's count the number of 1s. The right side has: first column (vertical) 3? No, the right side: top three are stacked (1,1,1), then two rows with two 1s each (so 2 rows × 2 = 4). So total 3 + 4 = 7? Wait, no, the left side: 3t + 5*(-1) = 3t -5. Right side: number of 1s. Let's count the yellow squares: first column (vertical) has 5? Wait no, the right side: top three are 1,1,1 (three), then next two rows (each row has two 1s) so 2 rows × 2 = 4. So total 3 + 4 = 7. So equation: 3t -5 = 7.

Step2: Solve for t

Add 5 to both sides: \( 3t -5 +5 = 7 +5 \) → \( 3t = 12 \).
Divide both sides by 3: \( t = \frac{12}{3} = 4 \). Wait, but maybe I miscounted. Wait left side: 3 t's and 5 (-1)s. Right side: let's count the 1s again. The right side: first column (vertical) has 5? No, the right side figure: top three are 1 (each), then two rows with two 1s (so row 4: two 1s, row 5: two 1s). So total 3 + 2 + 2 = 7. So 3t -5 =7 → 3t=12 → t=4. Wait, but maybe the right side has 7? Wait, let's check again. Left: 3t + 5*(-1) = 3t -5. Right: number of 1s. Let's count the yellow squares: first column (vertical) 5[SSE Completed, Client Connection Error][SSE onError error]